MCQs Physics Chapter 12 - Class 12

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Al-Huda Science Academy has designed Class 12 MCQs Physics Chapter 12 Electrostatics for board, MdCat and ECAT preparation. These MCQs help students to prepare for their entry test papers.

Chapter 12 Electrostatics includes topics:

Electric field Intensity
Electric Flux
Gauss’s Law and Applications
Electrical Potential
Electrical Field as Potential Gradient
Electron Volt
Millikan’s Oil Drop Method
Capacitance
Energy Stored in capacitor

MCQs Physics Chapter 12 Electrostatics

Results

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#1. In Millikan’s Oil drop method, charge on oil droplet is integral multiple of:

6.63 × 10^-34 C

1.6 × 10^-19 C

6.673 × 10^-11 C

1.6 × 10^19 C

#2. Gauss’ law applied to find:

Coulomb's law

Electric field Intensity

Electrical energy

Electric field lines

#3. Єr has unit:

#4. Dimensions of RC =

[T]

[ΩQ]

[TC]

[Ωs]

#5. Electric Field Intensity Works on:

All Units

Positive Units

Neutral Units

Negative Units

#6. 1pF =

10^-6 F

10^-3 F

10^-9 F

10^-12 F

#7. Maximum charge deposits on plate of capacitor is:

63%

61%

64%

62%

#8. Formula of Gauss’ law is:

Φ=m/Єo

Φ=A/Єo

Φ=q/Єo

Φ=Єo/q

#9. Capacitor is used to store:

potential difference

density

volts

charges

#10. In Millikan’s Oil Drop Method, the charge on oil drop is due to:

friction

gravitational energy

work

electrical energy

#11. Using Gauss’ law, value of E for infinite sheet is:

σ/Єo

σ/2Єo

Double

#12. Capacitance in vacuum is:

Єod/A

AЄo/d

A/Єod

AЄod

#13. Which device records voltage between points on human skin generated by brain?

ECG

EEG

COVID

MRI

#14. Electric Field Intensity is:

Vector Quantity

Scalar Quantity

Base Quantity

All

#15. Surface charge density σ =

σA

σ/A

q/A

#16. The unit of electric flux is:

NC/m2

N2m/C

Nm2/C

C2/Nm

#17. Drag force F =

6/πηrv

6πη/rv

6πηrv

1/6πηrv

#18. Capacitor stores energy in the form of:

magnetic field lines

surface charges

electric field lines

All

#19. Using Gauss’ Law, value of E between two oppositely charged parallel plates is:

σ/2Єo

1/2Єo

2Єo/σ

σ/Єo

#20. Charging and Discharging of capacitor is a process:

in motion

off and on

continuous

in rest

#21. The branch of Physics deals with charges at rest is:

Electrostatics

Electrodynamics

Electromagnetism

Electrochemistry

#22. Q=±ne is called:

Amount of charge

Uniformity of charge

Quantization of charge

Magnetization of charge

#23. Electric flux will be minimum if:

θ=270

θ=90

θ=180

θ=0

#24. In Millikan’s Oil Drop Method, the charge on oil drop is:

no charge

positive

negative

None

#25. Sharks have special organ to detect potential difference is:

Ampullae of Echinodermata

Ampulla of Rectum

Ampulla of Fallopian Tube

Ampullae of Lorenzini

#26. Capacitor stops:

A.C

D.C

Volts

Charges

#27. Electric flux is a:

All

Scalar Quantity

Base Quantity

Vector Quantity

#28. 1V=

1C/1J

1JC

All

1J/1C

#29. Which device records voltage between points on human skin generated by heart?

MRI

EEG

COVID

ECG

#30. The Unit for electric field intensity is:

C/Ns

Nm/C

C/Nm

Ns/C

#31. Time constant of charging and discharging of a capacitor t =

R/V

RxC

RxV

V/R

#32. 1eV =

1.6 × 10^-19 J

6.25 × 10^-19 J

1.6 × 10^-25 J

6.25 × 10^25 J

#33. Gauss’ law for unit positive charge is:

Φ=Єo/q

Φ=q/Єo

Φ=Єo

Φ=1/Єo

#34. Wind Shield Wipers works on:

charging and discharging

electric field intensity

Gauss' law

Ohm's law

#35. Gauss’ law is applicable on:

Gaussian Surface

Hollow Surface

Rectangular Surface

Spherical Surface

#36. The formula for electric flux is:

Φ=E.A

Φ=B.A

Φ=0

Φ=L.A

#37. Capacitance in medium is:

AЄo/d

A/ЄoЄrd

AЄo/Єrd

AЄoЄr/d

#38. 1Ω x 1F =

1eV

#39. 1μF =

10^-6 F

10^-9 F

10^-3 F

10^-12 F

#40. 1J =

6.25 × 10^-19 eV

1.6 × 10^17 eV

6.25 × 10^18 eV

1.6 × 10^-19 eV

#41. Sharks can detect potential difference upto:

micro volt

nano volt

pico volt

mili volt

#42. Using Gauss’ law, value of E for hollow sphere is:

Double

σ/2Єo

σ/Єo

#43. Electric flux will be maximum if:

θ=0

θ=180

θ=270

θ=90

#44. Gaussian surface is:

Uniform and Imaginary

Non-Uniform and Real

Uniform and Real

Non-Uniform and Imaginary

#45. In Millikan’s Oil Drop Method, the magnitude of charge q =

mgd/v

mgv/d

mg/dv

dv/mg

Finish

MCQs Physics Chapter 12 Electrostatics

Results

#1. In Millikan’s Oil drop method, charge on oil droplet is integral multiple of:

#2. Gauss’ law applied to find:

#3. Єr has unit:

#4. Dimensions of RC =

#5. Electric Field Intensity Works on:

#6. 1pF =

#7. Maximum charge deposits on plate of capacitor is:

#8. Formula of Gauss’ law is:

#9. Capacitor is used to store:

#10. In Millikan’s Oil Drop Method, the charge on oil drop is due to:

#11. Using Gauss’ law, value of E for infinite sheet is:

#12. Capacitance in vacuum is:

#13. Which device records voltage between points on human skin generated by brain?

#14. Electric Field Intensity is:

#15. Surface charge density σ =

#16. The unit of electric flux is:

#17. Drag force F =

#18. Capacitor stores energy in the form of:

#19. Using Gauss’ Law, value of E between two oppositely charged parallel plates is:

#20. Charging and Discharging of capacitor is a process:

#21. The branch of Physics deals with charges at rest is:

#22. Q=±ne is called:

#23. Electric flux will be minimum if:

#24. In Millikan’s Oil Drop Method, the charge on oil drop is:

#25. Sharks have special organ to detect potential difference is:

#26. Capacitor stops:

#27. Electric flux is a:

#28. 1V=

#29. Which device records voltage between points on human skin generated by heart?

#30. The Unit for electric field intensity is:

#31. Time constant of charging and discharging of a capacitor t =

#32. 1eV =

#33. Gauss’ law for unit positive charge is:

#34. Wind Shield Wipers works on:

#35. Gauss’ law is applicable on:

#36. The formula for electric flux is:

#37. Capacitance in medium is:

#38. 1Ω x 1F =

#39. 1μF =

#40. 1J =

#41. Sharks can detect potential difference upto:

#42. Using Gauss’ law, value of E for hollow sphere is:

#43. Electric flux will be maximum if:

#44. Gaussian surface is:

#45. In Millikan’s Oil Drop Method, the magnitude of charge q =

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