Al-Huda Science Academy is focusing not only on short questions and long questions but also on MCQs of Chapter 8 Chemistry Class 11. Entry Tests required a lot of effort on Multiple Choice Questions that should be of conceptual in nature. The users can participate without login to MCQs test. All MCQs are taken from the past papers of Punjab Boards including Bahawalpur Board, DG Khan Board, Faisalabad Board, Gujranwala Board, Lahore Board, Multan Board, Rawalpindi Board, Sahiwal Board and Sargodha Board. Chapter 8 of F.Sc Part 1 Chemistry is based on Chemical Equilibrium. In this chapter, students will learn about concepts of:
Concepts of Chemical Reactions, and their properties.
MCQs of Chapter 8 Chemistry Class 11
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#1. pH of soft drinks at 25 C is about:
#2. The ionization constant of pure water(Kw) at 25 C is:
#3. The pH of Gastric juice is :
#4. For which system does the equilibrium constant Kc has units of :
#5. pH of pure water is :
#6. pOH of water is :
#7. The pH of human blood is:
#8. The nature of Milk is:
#9. Which statement about the following equilibrium is correct: 2SO2 + O2⇌ 2SO3 ΔH=-188.3 kj/mole
#10. Optimum temperature for the synthesis of ammonia by Haber’s process is :
#11. The term pH was introduced by:
#12. Which one affects the value of Kc :
#13. Rain water is:
#14. Optimum pressure in Haber’s process for synthesis of ammonia is:
#15. The pH of milk of Magnesia is :
#16. Acid having Ka >1 will be:
#17. The pH of 10^-3 mol dm^-3 of an aqueos solution of H2SO4 is :
#18. Which law was derived by C.M Guldberg and P. Waage in 1864
#19. Approximate pH of apple is :
#20. The unit of Qc for reaction N2+O2 ⇌2NO will be
#21. The units of Kc for the reaction of ammonia synthesis are:
#22. pH of bananas is :
#23. In the presence of common ion the ionization of an electrolyte will:
#24. By adding NH4Cl to NH4OH solution.The ionization of NH4OH:
#25. The pH of 10^-4 mol/dm^3 of Ba(OH)2 is
#26. When Kc value of a reaction is very small, the equilibrium process lies to:
#27. The units for Kw of H2O are :
#28. Sum of pKa and pKb is equal to:
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