Physics Chapter 4 Class 9 MCQs Online Test

Al-Huda Science Academy has designed Physics Chapter 4 Class 9 MCQs for board preparation. Most of the questions are from the previous board papers. These are helping material for all type of students. Must share to your fellows if helpful.

Time allocated to each question is 30 seconds.

Physics Chapter 4 Class 9 MCQs

Results

-

Congratulations….

You have secured more than 70% to pass the test.

Feel Free to Try Again….

You have secured less than 70% to pass the test.

Click Here to Test Again

#1. In a right triangle, length of base is 4 cm and perpendicular is 3cm. Its tanθ is equal to:

#2. The direction of force with x-axis is given by:

#3. The net torque acting on a rotating body with uniform speed is:

#4. sin30° = _____.

#5. A force of 10N is making an angle of 30° with the horizontal. Its horizontal component will be:

#6. Complete equation Fy/Fx = ________

#7. The states of equilibrium are:

#8. The number of forces that can be added by head to tail rule are:

#9. If Fy=4N, Fx=3N, what is magnitude of resultant force?

#10. Racing cars are made stable by:

#11. The centre of gravity of a sphere is:

#12. The forces that are parallel to each other and have same direction are:

#13. Two equal but unlike parallel forces having different line of action produce:

#14. Torque depends on:

#15. The centre of gravity of a triangle is:

#16. A force of 10N is making an angle of 60° with x-axis then its horizontal component will be:

#17. cos30° = _____.

#18. S.I. unit of torque is:

#19. sin45° = _____.

#20. The value of sin90 is:

#21. A body is in equilibrium when its:

#22. Second condition of equilibrium is:

#23. The centre of gravity of uniform ______ is the point of intersection of its diagonals.

#24. cos90 = ______.

#25. A couple is formed by:

#26. The centre of gravityof an irregular shaped body can be found with the help of:

#27. sin60° = _____.

#28. The symbol of sigma is:

#29. A body is in neutral equilibrium when its centre of gravity:

#30. The direction of resultant vector can be found by:

#31. The value of tan45° is ________.

#32. Number of factors on which torque depends:

#33. cos60° = _____.

#34. When centre of gravity is at the highest position, body will be in:

#35. According to second condition of equilibrium must be zero:

#36. If force is 200N and legth of spanner is 0.15m then torque will be:

#37. First condition of equilibrium is:

#38. The moment arm is represented by a sign:

#39. Turning effect of a force is:

#40. sinθ = _____.

#41. cosθ = _____.

#42. The number of perpendicular components of a vector are:

#43. The formula of torque is:

Finish

Comments

No comments yet. Why don’t you start the discussion?

    Leave a Reply

    Your email address will not be published. Required fields are marked *