Al-Huda Science Academy has designed Physics Chapter 4 Class 9 MCQs for board preparation. Most of the questions are from the previous board papers. These are helping material for all type of students. Must share to your fellows if helpful.

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Physics Chapter 4 Class 9 MCQs

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#1. cos60° = _____.

0.5

0.5

1.732

1.732

1

1

0.866

0.866

#2. The states of equilibrium are:

9

9

6

6

3

3

12

12

#3. The centre of gravity of a sphere is:

radius of sphere

radius of sphere

none

none

outside the sphere

outside the sphere

centre of sphere

centre of sphere

#4. The forces that are parallel to each other and have same direction are:

resultant forces

resultant forces

like parallel forces

like parallel forces

unlike parallel forces

unlike parallel forces

net parallel forces

net parallel forces

#5. The centre of gravity of a triangle is:

point of intersection of diagonals

point of intersection of diagonals

point of intersection of medians

point of intersection of medians

center

center

center of axis

center of axis

#6. sin60° = _____.

1.732

1.732

0.5

0.5

1

1

0.866

0.866

#7. Two equal but unlike parallel forces having different line of action produce:

equilibrium

equilibrium

a couple

a couple

a torque

a torque

neutral equilibrium

neutral equilibrium

#8. sin30° = _____.

0.5

0.5

1.732

1.732

1

1

0.866

0.866

#9. If force is 200N and legth of spanner is 0.15m then torque will be:

10Nm

10Nm

20Nm

20Nm

15Nm

15Nm

30Nm

30Nm

#10. In a right triangle, length of base is 4 cm and perpendicular is 3cm. Its tanθ is equal to:

0.75

0.75

0.89

0.89

0.6

0.6

0.8

0.8

#11. The direction of resultant vector can be found by:

θ = Tan-1 Fy/Fx

θ = Tan-1 Fy/Fx

θ = Tan Fy/Fx

θ = Tan Fy/Fx

θ = Tan-1 Fx/Fy

θ = Tan-1 Fx/Fy

θ = Tan Fx/Fy

θ = Tan Fx/Fy

#12. The value of tan45° is ________.

1

1

0.707

0.707

0.866

0.866

0.5

0.5

#13. The number of forces that can be added by head to tail rule are:

2

2

4

4

3

3

any number

any number

#14. Second condition of equilibrium is:

ΣF=0

ΣF=0

Στ=0

Στ=0

All

All

ΣW=0

ΣW=0

#15. A body is in neutral equilibrium when its centre of gravity:

keeps its height if displaced

keeps its height if displaced

is situated at its bottom

is situated at its bottom

is at lowest position

is at lowest position

is at its highest position

is at its highest position

#16. The formula of torque is:

τ = L x F

τ = L x F

E = F x L

E = F x L

E = F x T

E = F x T

L = F x E

L = F x E

#17. Complete equation Fy/Fx = ________

cosθ

cosθ

tanθ

tanθ

cosecθ

cosecθ

sinθ

sinθ

#18. cosθ = _____.

base/perpendicular

base/perpendicular

base/hypotenuse

base/hypotenuse

perpendicular/hypotenuse

perpendicular/hypotenuse

perpendicular/base

perpendicular/base

#19. First condition of equilibrium is:

ΣF=0

ΣF=0

All

All

Στ=0

Στ=0

ΣF=0, Στ=0

ΣF=0, Στ=0

#20. cos90 = ______.

0.707

0.707

0.5

0.5

1

1

0

0

#21. The net torque acting on a rotating body with uniform speed is:

2

2

3

3

1

1

0

0

#22. sin45° = _____.

0.707

0.707

1

1

0.5

0.5

0

0

#23. Racing cars are made stable by:

decreasing their width

decreasing their width

lowering their centre of gravity

lowering their centre of gravity

decreasing their mass

decreasing their mass

increasing their speed

increasing their speed

#24. If Fy=4N, Fx=3N, what is magnitude of resultant force?

5N

5N

8.7N

8.7N

7N

7N

4N

4N

#25. The centre of gravity of uniform ______ is the point of intersection of its diagonals.

circular ring

circular ring

solid cylinder

solid cylinder

square sheet

square sheet

triangle sheet

triangle sheet

#26. The value of sin90 is:

0.5

0.5

0

0

0.707

0.707

1

1

#27. S.I. unit of torque is:

Nm-1

Nm-1

Ns

Ns

Ns-1

Ns-1

Nm

Nm

#28. A force of 10N is making an angle of 30° with the horizontal. Its horizontal component will be:

8.7N

8.7N

5N

5N

7N

7N

4N

4N

#29. A couple is formed by:

two equal and opposite forces not in same line

two equal and opposite forces not in same line

two equal and opposite forces in same line

two equal and opposite forces in same line

two forces perpendicular to each other

two forces perpendicular to each other

two like parallel forces

two like parallel forces

#30. According to second condition of equilibrium must be zero:

rotational force

rotational force

linear acceleration

linear acceleration

angular acceleration

angular acceleration

sum of torques

sum of torques

#31. Number of factors on which torque depends:

3

3

1

1

2

2

4

4

#32. A body is in equilibrium when its:

speed and acceleration are uniform

speed and acceleration are uniform

acceleration is uniform

acceleration is uniform

acceleration is zero

acceleration is zero

speed is uniform

speed is uniform

#33. The direction of force with x-axis is given by:

θ = Tan Fy/Fx

θ = Tan Fy/Fx

θ = Tan Fx/Fy

θ = Tan Fx/Fy

θ = Tan-1 Fx/Fy

θ = Tan-1 Fx/Fy

θ = Tan-1 Fy/Fx

θ = Tan-1 Fy/Fx

#34. The number of perpendicular components of a vector are:

3

3

1

1

4

4

2

2

#35. The moment arm is represented by a sign:

F

F

L

L

N

N

T

T

#36. A force of 10N is making an angle of 60° with x-axis then its horizontal component will be:

7N

7N

4N

4N

8.7N

8.7N

5N

5N

#37. cos30° = _____.

0.5

0.5

1

1

1.732

1.732

0.866

0.866

#38. Torque depends on:

force and velocity

force and velocity

force and moment arm

force and moment arm

force and mass

force and mass

mass and velocity

mass and velocity

#39. sinθ = _____.

perpendicular/hypotenuse

perpendicular/hypotenuse

perpendicular/base

perpendicular/base

base/perpendicular

base/perpendicular

base/hypotenuse

base/hypotenuse

#40. The symbol of sigma is:

τ

τ

µ

µ

θ

θ

Σ

Σ

#41. When centre of gravity is at the highest position, body will be in:

unstable equilibrium

unstable equilibrium

None

None

neutral equilibrium

neutral equilibrium

stable equilibrium

stable equilibrium

#42. Turning effect of a force is:

moment

moment

torque and momentum

torque and momentum

torque

torque

couple

couple

#43. The centre of gravityof an irregular shaped body can be found with the help of:

wedge

wedge

screw gauge

screw gauge

plumb line

plumb line

meter rule

meter rule

Finish