Al-Huda Science Academy has designed Physics Chapter 4 Class 9 MCQs for board preparation. Most of the questions are from the previous board papers. These are helping material for all type of students. Must share to your fellows if helpful.

Time allocated to each question is 30 seconds.

Physics Chapter 4 Class 9 MCQs

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#1. A body is in neutral equilibrium when its centre of gravity:

#2. Two equal but unlike parallel forces having different line of action produce:

#3. sin30° = _____.

#4. Turning effect of a force is:

#5. The forces that are parallel to each other and have same direction are:

#6. The centre of gravity of a sphere is:

#7. Racing cars are made stable by:

#8. cos90 = ______.

#9. A couple is formed by:

#10. The formula of torque is:

#11. S.I. unit of torque is:

#12. sinθ = _____.

#13. A body is in equilibrium when its:

#14. The value of sin90 is:

#15. The net torque acting on a rotating body with uniform speed is:

#16. The direction of resultant vector can be found by:

#17. The states of equilibrium are:

#18. The centre of gravity of uniform ______ is the point of intersection of its diagonals.

#19. cos30° = _____.

#20. If Fy=4N, Fx=3N, what is magnitude of resultant force?

#21. Complete equation Fy/Fx = ________

#22. cosθ = _____.

#23. sin60° = _____.

#24. When centre of gravity is at the highest position, body will be in:

#25. sin45° = _____.

#26. First condition of equilibrium is:

#27. The value of tan45° is ________.

#28. In a right triangle, length of base is 4 cm and perpendicular is 3cm. Its tanθ is equal to:

#29. Torque depends on:

#30. The symbol of sigma is:

#31. The number of forces that can be added by head to tail rule are:

#32. Number of factors on which torque depends:

#33. If force is 200N and legth of spanner is 0.15m then torque will be:

#34. A force of 10N is making an angle of 60° with x-axis then its horizontal component will be:

#35. The number of perpendicular components of a vector are:

#36. cos60° = _____.

#37. A force of 10N is making an angle of 30° with the horizontal. Its horizontal component will be:

#38. According to second condition of equilibrium must be zero:

#39. The centre of gravity of a triangle is:

#40. Second condition of equilibrium is:

#41. The centre of gravityof an irregular shaped body can be found with the help of:

#42. The moment arm is represented by a sign:

#43. The direction of force with x-axis is given by:

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By Ahsa.Pk

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