Al-Huda Science Academy has designed Physics Chapter 4 Class 9 MCQs for board preparation. Most of the questions are from the previous board papers. These are helping material for all type of students. Must share to your fellows if helpful.

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Physics Chapter 4 Class 9 MCQs

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#1. A body is in neutral equilibrium when its centre of gravity:#2. Two equal but unlike parallel forces having different line of action produce:#4. Turning effect of a force is:#5. The forces that are parallel to each other and have same direction are:

#6. The centre of gravity of a sphere is:#7. Racing cars are made stable by:#9. A couple is formed by:#10. The formula of torque is:

#11. S.I. unit of torque is:#13. A body is in equilibrium when its:#14. The value of sin90 is:#15. The net torque acting on a rotating body with uniform speed is:

#16. The direction of resultant vector can be found by:#17. The states of equilibrium are:#18. The centre of gravity of uniform ______ is the point of intersection of its diagonals.#20. If Fy=4N, Fx=3N, what is magnitude of resultant force?

#21. Complete equation Fy/Fx = ________#24. When centre of gravity is at the highest position, body will be in:

#26. First condition of equilibrium is:#27. The value of tan45° is ________.#28. In a right triangle, length of base is 4 cm and perpendicular is 3cm. Its tanθ is equal to:#30. The symbol of sigma is:

#31. The number of forces that can be added by head to tail rule are:#32. Number of factors on which torque depends:#33. If force is 200N and legth of spanner is 0.15m then torque will be:#34. A force of 10N is making an angle of 60° with x-axis then its horizontal component will be:#35. The number of perpendicular components of a vector are:

#37. A force of 10N is making an angle of 30° with the horizontal. Its horizontal component will be:#38. According to second condition of equilibrium must be zero:#39. The centre of gravity of a triangle is:#40. Second condition of equilibrium is:

#41. The centre of gravityof an irregular shaped body can be found with the help of:#42. The moment arm is represented by a sign:#43. The direction of force with x-axis is given by:

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