Physics Chapter 4 Class 9 MCQs Online Test

Al-Huda Science Academy has designed Physics Chapter 4 Class 9 MCQs for board preparation. Most of the questions are from the previous board papers. These are helping material for all type of students. Must share to your fellows if helpful.

Time allocated to each question is 30 seconds.

Physics Chapter 4 Class 9 MCQs

Results

-

Congratulations….

You have secured more than 70% to pass the test.

Feel Free to Try Again….

You have secured less than 70% to pass the test.

Click Here to Test Again

#1. When centre of gravity is at the highest position, body will be in:

unstable equilibrium

unstable equilibrium

stable equilibrium

stable equilibrium

None

None

neutral equilibrium

neutral equilibrium

#2. The value of sin90 is:

0.707

0.707

0

0

0.5

0.5

1

1

#3. The net torque acting on a rotating body with uniform speed is:

3

3

1

1

0

0

2

2

#4. The formula of torque is:

E = F x T

E = F x T

τ = L x F

τ = L x F

L = F x E

L = F x E

E = F x L

E = F x L

#5. The forces that are parallel to each other and have same direction are:

unlike parallel forces

unlike parallel forces

net parallel forces

net parallel forces

like parallel forces

like parallel forces

resultant forces

resultant forces

#6. A body is in equilibrium when its:

acceleration is zero

acceleration is zero

acceleration is uniform

acceleration is uniform

speed and acceleration are uniform

speed and acceleration are uniform

speed is uniform

speed is uniform

#7. sin30° = _____.

0.866

0.866

1

1

1.732

1.732

0.5

0.5

#8. The symbol of sigma is:

Σ

Σ

τ

τ

µ

µ

θ

θ

#9. cosθ = _____.

base/perpendicular

base/perpendicular

base/hypotenuse

base/hypotenuse

perpendicular/base

perpendicular/base

perpendicular/hypotenuse

perpendicular/hypotenuse

#10. The number of forces that can be added by head to tail rule are:

2

2

4

4

any number

any number

3

3

#11. The moment arm is represented by a sign:

L

L

F

F

T

T

N

N

#12. A couple is formed by:

two forces perpendicular to each other

two forces perpendicular to each other

two like parallel forces

two like parallel forces

two equal and opposite forces in same line

two equal and opposite forces in same line

two equal and opposite forces not in same line

two equal and opposite forces not in same line

#13. If force is 200N and legth of spanner is 0.15m then torque will be:

30Nm

30Nm

15Nm

15Nm

20Nm

20Nm

10Nm

10Nm

#14. Second condition of equilibrium is:

ΣF=0

ΣF=0

Στ=0

Στ=0

ΣW=0

ΣW=0

All

All

#15. According to second condition of equilibrium must be zero:

angular acceleration

angular acceleration

sum of torques

sum of torques

linear acceleration

linear acceleration

rotational force

rotational force

#16. Two equal but unlike parallel forces having different line of action produce:

neutral equilibrium

neutral equilibrium

a couple

a couple

equilibrium

equilibrium

a torque

a torque

#17. A force of 10N is making an angle of 30° with the horizontal. Its horizontal component will be:

5N

5N

4N

4N

7N

7N

8.7N

8.7N

#18. cos90 = ______.

0.5

0.5

0

0

1

1

0.707

0.707

#19. Turning effect of a force is:

torque

torque

torque and momentum

torque and momentum

moment

moment

couple

couple

#20. cos60° = _____.

1.732

1.732

0.5

0.5

1

1

0.866

0.866

#21. The centre of gravity of a sphere is:

centre of sphere

centre of sphere

radius of sphere

radius of sphere

outside the sphere

outside the sphere

none

none

#22. Torque depends on:

force and velocity

force and velocity

force and moment arm

force and moment arm

mass and velocity

mass and velocity

force and mass

force and mass

#23. The centre of gravityof an irregular shaped body can be found with the help of:

meter rule

meter rule

screw gauge

screw gauge

wedge

wedge

plumb line

plumb line

#24. Racing cars are made stable by:

increasing their speed

increasing their speed

decreasing their width

decreasing their width

decreasing their mass

decreasing their mass

lowering their centre of gravity

lowering their centre of gravity

#25. The direction of force with x-axis is given by:

θ = Tan Fx/Fy

θ = Tan Fx/Fy

θ = Tan-1 Fy/Fx

θ = Tan-1 Fy/Fx

θ = Tan Fy/Fx

θ = Tan Fy/Fx

θ = Tan-1 Fx/Fy

θ = Tan-1 Fx/Fy

#26. sin45° = _____.

0

0

0.707

0.707

1

1

0.5

0.5

#27. sin60° = _____.

0.5

0.5

0.866

0.866

1.732

1.732

1

1

#28. Complete equation Fy/Fx = ________

tanθ

tanθ

cosθ

cosθ

sinθ

sinθ

cosecθ

cosecθ

#29. cos30° = _____.

0.866

0.866

1

1

1.732

1.732

0.5

0.5

#30. In a right triangle, length of base is 4 cm and perpendicular is 3cm. Its tanθ is equal to:

0.89

0.89

0.75

0.75

0.6

0.6

0.8

0.8

#31. The value of tan45° is ________.

0.866

0.866

0.707

0.707

0.5

0.5

1

1

#32. The centre of gravity of a triangle is:

center

center

point of intersection of diagonals

point of intersection of diagonals

center of axis

center of axis

point of intersection of medians

point of intersection of medians

#33. S.I. unit of torque is:

Nm-1

Nm-1

Ns

Ns

Ns-1

Ns-1

Nm

Nm

#34. The centre of gravity of uniform ______ is the point of intersection of its diagonals.

square sheet

square sheet

circular ring

circular ring

triangle sheet

triangle sheet

solid cylinder

solid cylinder

#35. The states of equilibrium are:

3

3

12

12

9

9

6

6

#36. First condition of equilibrium is:

All

All

ΣF=0

ΣF=0

Στ=0

Στ=0

ΣF=0, Στ=0

ΣF=0, Στ=0

#37. A force of 10N is making an angle of 60° with x-axis then its horizontal component will be:

4N

4N

8.7N

8.7N

7N

7N

5N

5N

#38. sinθ = _____.

perpendicular/base

perpendicular/base

base/perpendicular

base/perpendicular

base/hypotenuse

base/hypotenuse

perpendicular/hypotenuse

perpendicular/hypotenuse

#39. The direction of resultant vector can be found by:

θ = Tan Fy/Fx

θ = Tan Fy/Fx

θ = Tan-1 Fx/Fy

θ = Tan-1 Fx/Fy

θ = Tan Fx/Fy

θ = Tan Fx/Fy

θ = Tan-1 Fy/Fx

θ = Tan-1 Fy/Fx

#40. If Fy=4N, Fx=3N, what is magnitude of resultant force?

5N

5N

4N

4N

7N

7N

8.7N

8.7N

#41. Number of factors on which torque depends:

1

1

3

3

4

4

2

2

#42. The number of perpendicular components of a vector are:

3

3

4

4

1

1

2

2

#43. A body is in neutral equilibrium when its centre of gravity:

is at its highest position

is at its highest position

keeps its height if displaced

keeps its height if displaced

is situated at its bottom

is situated at its bottom

is at lowest position

is at lowest position

Finish